Megatest

                      (mt:test-set-state-status-by-id run-id test-id "NOT_STARTED" "ZERO_ITEMS" "This test has no items which match test pattern.")))
                
                (for-each (lambda (my-itemdat)
                            (let* ((new-test-record (let ((newrec (make-tests:testqueue)))
                                                      (vector-copy! test-record newrec)
                                                      newrec))
                                   (my-item-path (item-list->path my-itemdat))

                                   (newtestname (db:test-make-full-name hed my-item-path)))    ;; test names are unique on testname/item-path
                              (tests:testqueue-set-items!     new-test-record #f)
                            (tests:testqueue-set-itemdat!   new-test-record my-itemdat)
                            (tests:testqueue-set-item_path! new-test-record my-item-path)
                            (hash-table-set! test-records newtestname new-test-record)
                            (set! tal (append tal (list newtestname)))))  ;; since these are itemized create new test names testname/itempath
                          items-in-testpatt)))
                          
            


	  ;; At this point we have possibly added items to tal but all must be handed off to 
	  ;; INNER COND logic. I think loop without rotating the queue 
	  ;; (loop hed tal reg reruns))
	  ;; (let ((newtal (append tal (list hed))))  ;; We should discard hed as it has been expanded into it's items? Yes, but only if this *is* an itemized test
	  ;; (loop (car newtal)(cdr newtal) reg reruns)
	  (if (null? tal)