Megatest

         (registry-mutex        (make-mutex))
         (num-retries           0)
         (max-retries           (configf:lookup *configdat* "setup" "maxretries"))
         (max-concurrent-jobs   (configf:lookup-number *configdat* "setup" "max_concurrent_jobs" default: 50))
         (reglen                (if (number? reglen-in) reglen-in 1))
         (last-time-incomplete  (- (current-seconds) 900)) ;; force at least one clean up cycle
         (last-time-some-running (current-seconds))
	 (incoming-tests        '()) ;; queue up incoming tests here to tack on to tal when it gets low
         ;; (tdbdat                (tasks:open-db))
         (runsdat (make-runs:dat
                   ;; hed: hed
                   ;; tal: tal
                   ;; reg: reg
                   ;; reruns: reruns
                   reglen: reglen

                                   (newtestname (db:test-make-full-name hed my-item-path)))    ;; test names are unique on testname/item-path
                              (tests:testqueue-set-items!     new-test-record #f)
                              (tests:testqueue-set-itemdat!   new-test-record my-itemdat)
                              (tests:testqueue-set-item_path! new-test-record my-item-path)
                              (hash-table-set! test-records newtestname new-test-record)
			      ;; BUG: This next line sucks up a lot of horsepower
			      ;; (set! tal (append tal (list newtestname)))
			      ;; (set! tal (cons newtestname tal)) ;; 4/6/2023 - try using cons, does it matter if the test gets added at the beginning?
			      (set! incoming-tests (cons newtestname incoming-tests))
			      (set! tal (append tal (list newtestname)))))  ;; since these are itemized create new test names testname/itempath
			      ))  ;; since these are itemized create new test names testname/itempath
                          items-in-testpatt)))
          
          
	  (if (< (length tal) 20)
	      (begin
		(set! tal (append tal (reverse incoming-tests)))
		(set! incoming-tests '())))

	  ;; At this point we have possibly added items to tal but all must be handed off to 
	  ;; INNER COND logic. I think loop without rotating the queue 
	  ;; (loop hed tal reg reruns))
	  ;; (let ((newtal (append tal (list hed))))  ;; We should discard hed as it has been expanded into it's items? Yes, but only if this *is* an itemized test
	  ;; (loop (car newtal)(cdr newtal) reg reruns)
	  (if (null? tal)